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MCAT Question of the Day
Q:
In the combustion of methane, what is the change in oxidation state of the carbon atom from the left side of the reaction to the right and what is the reducing agent? The reaction is as follows: CH
4
+ 2O
2
→ CO
2
+ 2H
2
O
A
+4 and CH
4
is the reducing agent.
B
+8 and O
2
is the reducing agent.
C
+4 and O
2
is the reducing agent.
D
+8 and CH
4
is the reducing agent.
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