Jul '15
2
MCAT Question of the Day | MCAT Course


  • Q:

    During the first step of glucose metabolism, an enzyme drives catalysis and binds glucose in its active site. A second site exists (away from the active site) which binds ATP (the eventual end-product of glucose metabolism). Which of the following is NOT correct in describing the mechanism behind the ATP-binding site on this enzyme?

     

    A

    The ATP-binding site is an example of feedback inhibition

    B

    ATP acts as a non-competitive inhibitor of the enzyme.

    C

    The enzyme is less active when ATP is present in high concentrations

    D

    The enzyme is more active when ATP is present in high concentrations




    Tags: Enzyme Structure and Function | Glycolysis, Gluconeogenesis, PPP | Suggest a tag
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