Jun '14
13
MCAT Question of the Day | MCAT Course


  • Q:

    Given the potentials of the following half-reactions, how would the net reaction proceed if set up to run as a spontaneous reaction?

    Al3+ + 3e- → AlE° = -1.66 V
    Fe3+ + 3e- → FeE° = -0.04 V


     

    A

    Al3+ + Fe3+ → Al + Fe

    B

    Al3+ + Fe → Al + Fe3+

    C

    Al + Fe3+ → Fe + Al3+

    D

    Al + Fe → Al3+ + Fe3+




    Tags: Thermochemistry | Quantitative Skills | Suggest a tag
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